Work Step by Step
Given $$y=|x+3|-8$$ Rewrite as: $y=|x-(-3)+(-8)$ Thus, we have $a=1\\k=-3\\h=-8$ Find the y-intercept: $y=|0+3|-8=-5$ Find another point: $x=1 \rightarrow y=-4\\x=2\rightarrow y=-3\\x=11\rightarrow y= 0$
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