Answer
SEE BELOW
Work Step by Step
Given $$y=|x+3|-8$$
Rewrite as: $y=|x-(-3)+(-8)$
Thus, we have $a=1\\k=-3\\h=-8$
Find the y-intercept: $y=|0+3|-8=-5$
Find another point: $x=1 \rightarrow y=-4\\x=2\rightarrow y=-3\\x=11\rightarrow y= 0$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 12 Sequences and Series - Cumulative Review - Page 848: 3
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