## Algebra 2 (1st Edition)

Published by McDougal Littell

# Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 10

#### Answer

$0.2119$

#### Work Step by Step

$\overline{x}=np=0.04\cdot460=18.4$ $\sigma=\sqrt{np(1-p)}=\sqrt{460(0.04)(0.96)}\approx4.2$ Thus $P(x\leq15)\approx P(z\leq\frac{15-18.4}{4.2})\approx P(z\leq-0.8)=0.2119$

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