Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 16



Work Step by Step

$\overline{x}=np=0.25\cdot192=48$ $\sigma=\sqrt{np(1-p)}=\sqrt{192(0.75)(0.25)}=6$ Thus $P(x\geq42)=1-P(x\leq42)\approx 1-P(z\leq\frac{42-48}{6})=1-P(z\leq-1)=1-0.1587=0.8413$
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