Answer
$0.9987$
Work Step by Step
$\overline{x}=np=0.25\cdot192=48$
$\sigma=\sqrt{np(1-p)}=\sqrt{192(0.75)(0.25)}=6$
Thus $P(x\leq66)\approx P(z\leq\frac{66-48}{6})=P(z\leq3)=0.9987$
Algebra 2 (1st Edition)
by Larson, Ron; Boswell, Laurie; Kanold, Timothy D.; Stiff, Lee
Published by
McDougal Littell
ISBN 10:
0618595414
ISBN 13:
978-0-61859-541-9
Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 17
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