Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 11



Work Step by Step

$\overline{x}=np=0.04\cdot460=18.4$ $\sigma=\sqrt{np(1-p)}=\sqrt{460(0.04)(0.96)}\approx4.2$ Thus $P(x\geq12)=1-P(x\leq12)\approx 1-P(z\leq\frac{12-18.4}{4.2})\approx 1-P(z\leq-1.5)=1-0.0668=0.9332$
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