Algebra 2 (1st Edition)

Published by McDougal Littell
ISBN 10: 0618595414
ISBN 13: 978-0-61859-541-9

Chapter 11 Data Analysis and Statistics - Extension - Approximate Binomial Distributions and Test Hypotheses - Practice - Page 765: 18



Work Step by Step

$\overline{x}=np=0.25\cdot192=48$ $\sigma=\sqrt{np(1-p)}=\sqrt{192(0.75)(0.25)}=6$ Thus $P(36\leq x\leq60)\approx P(z\leq\frac{60-48}{6})-P(z\leq\frac{36-48}{6})=P(z\leq2)-P(\leq-2)=0.9772-0.0228=0.9544$
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