Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Practice and Problem-Solving Exercises - Page 545: 32

Answer

Please see the graph.
1534116588

Work Step by Step

The graph was made using graphing software. $y=\frac{1}{2}x^2+8x-20$ vertex: $x=-b/2a$ $x = -(8)/2*(.5)$ $x = -8/1$ $x = -8$ $y=\frac{1}{2}x^2+8x-20$ $y=\frac{1}{2}*8^2+8*-8-20$ $y=.5*64-64-20$ $y=32-64-20$ $y=-52$ $(-8,-52)$ Two points on the curve: $x=0$ $y=\frac{1}{2}*0^2+8*0-20$ $y= .5*0+0 - 20$ $y = -20$ $(0,-20)$ Since the distance from 0 to the axis of symmetry is 8 units, we also know $(8,-52)$ is on the curve.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.