## Algebra 1

The graph was made using graphing software. $y=1.5x^2-3x+2$ vertex $x=-b/2a$ $x=-(-3)/2(1.5)$ $x = 3/3 = 1$ $y=1.5x^2-3x+2$ $y=1.5*1^2-3*1+2$ $y=1.5-3+2$ $y=.5$ $(1,.5)$ Two other points on the curve: $x=0$ $y=1.5*0^2-3*0+2$ $y= 1.5*0 -0 +2$ $y = 0-0+2 = 2$ $(0,2)$ The distance from 0 to 1 (the axis of symmetry) is 1, so we also know $(2,2)$ is on the curve.