## Algebra 1

The graph was created using graphing software. $y=.25x^2-2x-1$ vertex $x = -b/2a$ $x= -(-2)/2*(.25)$ $x = 2/.5 = 4$ $y=.25*4^2-2*4-1$ $y=.25*16 -8 -1$ $y=4 - 8-1$ $y = -5$ $(4, -5)$ Two other points on the line $x=0$ $y=.25*0^2-2*0-1$ $y= .25*0 - 0 -1$ $y = 0-0-1 = -1$ $(0,-1)$ The difference between 0 and 4 (the axis of symmetry) is 4, so the point $(8, -1)$ is also on the curve.