## Algebra 1

$y = 2x^{2} - 6x + 1$ The standard form for a quadratic equation is $y = ax^{2} + bx + c$ So a= 2, b= -6, and c= 1 Axis of symmetry: The formula for axis of symmetry is $x= \frac{-b}{2a}$ $x= \frac{-(-6)}{2(2)}$ $x= \frac{6}{4}$ x= 1.5 Vertex: Plug in the x value of the axis of symmetry to find the y value of the vertex. $y = 2x^{2} - 6x + 1$ $y = 2(1.5)^{2} - 6(1.5) + 1$ y= -3.5 The vertex is (1.5, -3.5) We plot the vertex on the graph. Since the a value is 2 and is positive the parabola opens upwards. So we graph a parabola starting from the vertex and then graphing it upwards.