# Chapter 9 - Quadratic Functions and Equations - 9-2 Quadratic Functions - Practice and Problem-Solving Exercises - Page 545: 29

#### Work Step by Step

The graph was made using graphing software. $f(x)=-\frac{4}{3}x^2-8x+8$ vertex $x= -b/2a$ $x= -(-8)/2*-(4/3)$ $x = 8/-8/3$ $x = -3$ $f(-3)=-\frac{4}{3}(-3)^2-8*(-3)+8$ $f(-3)=-4/3 *9+24+8$ $f(-3) = -12 + 24+8$ $f(-3) = 20$ Two other points on the curve $f(0) = -\frac{4}{3}(0)^2-8*(0)+8$ $f(0) = -4/3 *0-0+8$ $f(0) = 0+0+8 = 8$ $(0,8)$ Since $(0,8)$ is three units from the axis of symmetry, we also know $(-6,8)$ is on the graph.

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