Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 510: 46

(9v-1)(11v-9)

Given the polynomial $99v^{2}$ - 92v + 9 *** We break of the middle term into two factors that add to give -92 and multiply to give +891. The two numbers are -11 and -81. $99v^{2}$ - 11v - 81v + 9 We take the GCD of the first two and the GCD of the last two terms. 11v(9v-1)-9(9v-1) We take (9v-1) and factor it out which gives us. (9v-1)(11v-9)