## Algebra 1

Given the polynomial $28h^{2}$ + 28h - 56 We see that the three terms have a common factor of 28 so we factor out 28. 28($h^{2}$ + h - 2) *** We break of the middle term into two factors that add to give +1 and multiply to give -2. The two numbers are +2 and -1. 28($h^{2}$ + 2h - h - 2) We take the GCD of the first two and the GCD of the last two terms. 28(h(h+2)-1(h+2)) We take (h+2) and factor it out which gives us. 28(h+2)(h-1)