## Algebra 1

Given the polynomial $66k^{2}$ + 57k + 12 We see that the three terms have a common factor of 3 so we factor out a 3. 3($22k^{2}$ + 19k + 4) *** We break of the middle term into two factors that add to give +19 and multiply to give 88. The two numbers are +8 and +11. 3($22k^{2}$ + 8k + 11k + 4) We take the GCD of the first two and the GCD of the last two terms. 3(2k(11k+4)+1(11k+4)) We take (11k+4) and factor it out which gives us. 3(2k+1)(11k+4)