Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises: 42

Answer

3(7y-4)(y+4)

Work Step by Step

Given the polynomial $21y^{2}$ + 72y - 48 We see that the three terms have a common factor of 3 so we factor out a 3. 3($7y^{2}$ + 24y - 16) *** We break of the middle term into two factors that add to give +24 and multiply to give -112. The two numbers are +28 and -4. 3($7y^{2}$ + 28y - 4y - 16) We take the GCD of the first two and the GCD of the last two terms. 3(7y(y+4)-4(y+4)) We take (y+4) and factor it out which gives us. 3(7y-4)(y+4)
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