## Algebra 1

Given the polynomial $36p^{2}$ + 114p - 20 We see that the three terms have a common factor of 2 so we factor out a 2. 2($18p^{2}$ + 57p - 10) *** We break of the middle term into two factors that add to give +57 and multiply to give -180. The two numbers are +60 and -3. 2($18p^{2}$ + 60p - 3p - 10) We take the GCD of the first two and the GCD of the last two terms. 2(6p(3p+10)-1(3p+10)) We take (3p+10) and factor it out which gives us. 2(6p-1)(3p+10)