Algebra 1

Published by Prentice Hall

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 27

3(3r-5)(r+2)

Work Step by Step

Given the polynomial $9r^{2}$ + 3r - 30 We see that the three terms have a common factor of 3 so we factor out a 3. 3($3r^{2}$ + r - 10) *** We break of the middle term into two factors that add to give +1 and multiply to give -10. The two numbers are +6 and -5. 3($3r^{2}$ + 6r - 5r - 10) We take the GCD of the first two and the GCD of the last two terms. 3(3r(r+2)-5(r+2)) We take (r+2) and factor it out which gives us. 3(3r-5)(r+2)

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