Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 15

(2k+3)(k-8)

Given the polynomial $2k^{2}$ -13k - 24 *** We break of the middle term into two factors that add to give -13 and multiply to give -48. The two numbers are -16 and +3. $2k^{2}$ -16k +3k - 24 We take the GCD of the first two and the GCD of the last two terms. 2k(k-8) +3(k-8) We take (k-8) and factor it out which gives us. (2k+3)(k-8)