Algebra 1

by Hall, Prentice

Published by Prentice Hall

ISBN 10: 0133500403

ISBN 13: 978-0-13350-040-0

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 21

Answer

(3x-4)(5x+2)

Work Step by Step

Given the polynomial $15x^{2}$ - 14x - 8 *** We break of the middle term into two factors that add to give -14 and multiply to give -120. The two numbers are -20 and +6. $15x^{2}$ - 20x + 6x - 8 We take the GCD of the first two and the GCD of the last two terms. 5x(3x-4) +2(3x-4) We take (3x-4) and factor it out which gives us. (3x-4)(5x+2)

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