Algebra 1

Published by Prentice Hall

Chapter 8 - Polynomials and Factoring - 8-6 Factoring ax(squared) + bx + c - Practice and Problem-Solving Exercises - Page 509: 26

2(x-4)(6x+1)

Work Step by Step

Given the polynomial $12x^{2}$ - 46x - 8 We see that the three terms have a common factor of 2 so we factor out a 2. 2($6x^{2}$ - 23x - 4) *** We break of the middle term into two factors that add to give -23 and multiply to give -24. The two numbers are -24 and +1. 2($6x^{2}$ - 24x + x - 4) We take the GCD of the first two and the GCD of the last two terms. 2(6x(x-4)+1(x-4)) We take (x-4) and factor it out which gives us. 2(x-4)(6x+1)

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