Answer
3(2s+3)(s+8)
Work Step by Step
Given the polynomial
$6s^{2}$ + 57s + 72
We see that the three terms have a common factor of 3 so we factor out a 3.
3($2s^{2}$ + 19s + 24)
*** We break of the middle term into two factors that add to give +19 and multiply to give +48. The two numbers are +16 and +3.
3($2s^{2}$ + 16s + 3s + 24)
We take the GCD of the first two and the GCD of the last two terms.
3(2s(s+8)+3(s+8))
We take (s+8) and factor it out which gives us.
3(2s+3)(s+8)
