## Algebra 1

$m=\frac{7}{3}$
We start with the given equation: $\frac{2}{3}+\frac{3m}{5}=\frac{31}{15}$ We multiply by the least common denominator: $15(\frac{2}{3}+\frac{3m}{5}=\frac{31}{15})$ $10+9m=31$ We subtract $10$ from each side of the equation: $10-10+9m=31-10$ We combine like terms: $9m=21$ Finally, we divide by $9$ on each side of the equation: $m=\frac{21}{9}$ This fraction can be reduced to $m=\frac{7}{3}$