## Algebra 1

$y=\frac{7}{25}$
We start with the given equation: $\frac{5y}{1}-\frac{3}{5}=\frac{4}{5}$ We multiply both sides by a common denominator, $5$, to clear the fractions from the equation: $5(\frac{5y}{1}-\frac{3}{5})=5(\frac{4}{5})$ $25y-3=4$ We add $3$ to both sides of the equation: $25y-3+3=4+3$ We combine like terms: $25y=7$ Finally, we divide both sides of the equation by 25: $y=\frac{7}{25}$