Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 2 - Solving Equations - 2-3 Solving Multi-Step Equations - Practice and Problem-Solving Exercises - Page 98: 21


$r = 6$

Work Step by Step

We are given the equation: $64=8(r+2)$ We begin by opening up the brackets on the right hand side of the equation as shown below: $64 = 8r + 16$ Next, we isolate the variable $r$ by subtracting $16$ from both sides of the equation as shown below: $64 - 16 = 8r + 16 - 16$ Simplify to get: $48 = 8r$ We then divide through by the coefficient of the variable $r$ as shown below: $\frac{48}{8} = \frac{8}{8}r$ Simplifying the equation, we have: $6 = r$ Rearranging it, we have: $r = 6$ Therefore, the equation has a possible solution at the point $r = 6$
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