Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 678: 9



Work Step by Step

Given: $\dfrac{x^2-4}{x+3} \times \dfrac{x^2+7x+12}{x-2}$ $\dfrac{x^2-4}{x+3} \times \dfrac{x^2+7x+12}{x-2}=\dfrac{(x^2-2^2)(x+3)(x+4)}{(x-2)(x+3)}$ $=\dfrac{(x-2)(x+2)(x+3)(x+4)}{(x-2)(x+3)}$ $=(x+2)(x+4)$ $=x^2+6x+8$
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