Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 678: 8



Work Step by Step

Given: $\dfrac{z-3}{3z} \times \dfrac{z+8}{z+2}$ $\dfrac{z-3}{3z} \times \dfrac{z+8}{z+2}=\dfrac{(z-3)(z+8)}{3z(z+2)}$ $=\dfrac{z^2+8z-3z-24}{3z^2+6z}$ $=\dfrac{z^2+5z-24}{3z^2+6z}$
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