## Algebra 1

$6(x-2); x \ne -2$
Given: $\dfrac{6x^2-24}{x+2}$ Need to find the common factors of the given expression. $\dfrac{6x^2-24}{x+2}=\dfrac{6(x^2-4)}{x+2}$ $=\dfrac{6(x+2)(x-2)}{x+2}$ If we put $x=-2$ then denominator becomes zero, which cannot be possible. After simplification, we get $=6(x-2); x \ne -2$