Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 678: 13



Work Step by Step

Given: $(6x^3-4x^2+2x) \times \dfrac{1}{4x^2}$ $(6x^3-4x^2+2x) \times \dfrac{1}{4x^2}=\dfrac{(6x^3-4x^2+2x)}{4x^2}$ $=\dfrac{2x(3x^2-2x+1)}{4x^2}$ $=\dfrac{(3x^2-2x+1)}{2x}$ $=\dfrac{3x}{2}-1+\dfrac{1}{2x}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.