Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 11 - Rational Expressions and Functions - Mid-Chapter Quiz - Page 678: 13

Answer

$\dfrac{3x}{2}-1+\dfrac{1}{2x}$

Work Step by Step

Given: $(6x^3-4x^2+2x) \times \dfrac{1}{4x^2}$ $(6x^3-4x^2+2x) \times \dfrac{1}{4x^2}=\dfrac{(6x^3-4x^2+2x)}{4x^2}$ $=\dfrac{2x(3x^2-2x+1)}{4x^2}$ $=\dfrac{(3x^2-2x+1)}{2x}$ $=\dfrac{3x}{2}-1+\dfrac{1}{2x}$
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