Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Get Ready - Page 597: 2



Work Step by Step

In order to solve for x in the equation $\frac{3}{a}$=$\frac{1}{6}$ we will apply the Cross Products Property of a Proportion that says that if $\frac{x}{y}$=$\frac{h}{g}$, where y$\ne$0 and g$\ne$0, then xg=hy. If we set x=3, y=a, h=1, and g=6, then we'll apply this property. (3)(6)=(1)(a) a=18
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