Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Get Ready - Page 597: 1



Work Step by Step

In order to solve for x in the equation $\frac{2}{3}$=$\frac{x}{15}$ we will apply the Cross Products Property of a Proportion that says that if $\frac{a}{b}$=$\frac{c}{d}$, where b$\ne$0 and d$\ne$0, then ad=bc. If we set a=2, b=3, c=x, and d=15, then we'll apply this property. (2)(15)=(x)(3) 30=3x Then, to solve for x, we'll divide by 3 on both sides of the equation $\frac{30}{3}$=$\frac{3x}{3}$ x=10
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