Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Get Ready - Page 597: 13

Answer

Please see the graph.
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Work Step by Step

$y=x^2+4$ vertex: $x=-b/2a$ $x=-0/2*1$ $x=0$ (axis of symmetry) $y=x^2+4$ $y=0^2+4$ $y=0+4=4$ $(0,4)$ One other point on the line: $x=1$ $y=x^2+4$ $y=1^2+4$ $y=1+4=5$ $(1,5)$
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