## Algebra 1

Published by Prentice Hall

# Chapter 10 - Radical Expressions and Equations - Get Ready - Page 597: 10

#### Answer

$9b^4 - 49$

#### Work Step by Step

Two ways to solve, using the Distributive Property and FOIL: Distributive Property: 1) Distribute the second factor ($3b^2 - 7$) to both the "$3b^2$" term and the "-7" term. Make sure you keep track of addition and subtraction signs. $3b(3b^2 - 7) + 7(3b^2 - 7)$ 2) Distribute the 3b to both terms inside the parentheses and the 7 to both terms inside the parentheses. $9b^3 - 21b^2 + 21b^2 - 49$ 3) Combining like terms and order from highest degree to lowest degree (the $b^2$ terms will cancel out: $-21b^2 + 21b^2 = 0b^2$) $9b^3 - 49$ FOIL: $(2h+3)(4-h)$ First + Outer + Inner + Last = $9b^4 - 21b^2 + 21b^2 - 49$ = $9b^4 - 49$ Combine like terms and order from highest degree to lowest degree (the $b^2$ terms will cancel out: $-21b^2 + 21b^2 = 0b^2$)

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.