Algebra 1

Published by Prentice Hall
ISBN 10: 0133500403
ISBN 13: 978-0-13350-040-0

Chapter 10 - Radical Expressions and Equations - Get Ready - Page 597: 14

Answer

Please see the graph.
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Work Step by Step

$y=2x^2+3$ vertex $x=-b/2a$ $x=-0/2*2$ $x=0$ $y=2x^2+3$ $y=2*0^2+3$ $y=2*0+3$ $y=0+3=3$ $(0,3)$ One other point on the curve $x=1$ $y=2x^2+3$ $y=2*1^2+3$ $y=2*1+3$ $y=2+3=5$ $(1,5)$
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