Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 604: 8


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Work Step by Step

We are given: $y=5x^2+8$ Let's list some values: $x=-2 \rightarrow y=28$ $x=-1 \rightarrow y=13$ $x=0 \rightarrow y=8$ $x=1 \rightarrow y=13$ $x=2 \rightarrow y=28$ The x-coordinate of the vertex is given by $x=\frac{-b}{2a}=0$ Find the y-coordinate of the vertex $y=5(0)^2+8=8$ Hence, the vertex is $(0,8)$.
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