#### Answer

See the graph

#### Work Step by Step

We are given:
$y=5x^2+8$
Let's list some values:
$x=-2 \rightarrow y=28$
$x=-1 \rightarrow y=13$
$x=0 \rightarrow y=8$
$x=1 \rightarrow y=13$
$x=2 \rightarrow y=28$
The x-coordinate of the vertex is given by $x=\frac{-b}{2a}=0$
Find the y-coordinate of the vertex $y=5(0)^2+8=8$
Hence, the vertex is $(0,8)$.