Answer
There are two solutions for the equation, $x=-3$ or $x=-4$
Work Step by Step
$x^2+7x+12=0$
$x^2+4x+3x+12=0$
$x(x+4)+3(x+4)=0$
$(x+3)(x+4)=0$
$x=-3$
or $x=-4$
There are two solutions for the equation, $x=-3$ or $x=-4$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 604: 23
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