Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 604: 10


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Work Step by Step

We are given: $y=-2x^2-3x+10$ Let's list some values: $x=-2 \rightarrow y=-10$ $x=-1 \rightarrow y=5$ $x=0 \rightarrow y=10$ $x=1 \rightarrow y=5$ $x=2 \rightarrow y=-10$ The x-coordinate of the vertex is given by $x=\frac{-b}{2a}=\frac{-(-3)}{2.(-2)}=-\frac{3}{4}$ Find the y-coordinate of the vertex $y=-2(-\frac{3}{4})^2-3(-\frac{3}{4})+10=\frac{89}{8}$ Hence, the vertex is $(-\frac{3}{4},\frac{89}{8})$.
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