#### Answer

See the graph

#### Work Step by Step

We are given:
$y=x^2-4$
Let's list some values:
$x=-2 \rightarrow y=0$
$x=-1 \rightarrow y=-3$
$x=0 \rightarrow y=-4$
$x=1 \rightarrow y=-3$
$x=2 \rightarrow y=0$
The x-coordinate of the vertex is given by $x=\frac{-b}{2a}=0$
Find the y-coordinate of the vertex $y=0^2-4=-4$
Hence, the vertex is $(0, -4)$.