Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - Chapter Review - Page 604: 7


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Work Step by Step

We are given: $y=x^2-4$ Let's list some values: $x=-2 \rightarrow y=0$ $x=-1 \rightarrow y=-3$ $x=0 \rightarrow y=-4$ $x=1 \rightarrow y=-3$ $x=2 \rightarrow y=0$ The x-coordinate of the vertex is given by $x=\frac{-b}{2a}=0$ Find the y-coordinate of the vertex $y=0^2-4=-4$ Hence, the vertex is $(0, -4)$.
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