Answer
There are two solutions for the equation, $x=\frac{3}{2}$ or $x=-\frac{2}{3}$
Work Step by Step
$3x^2-5x=-3x^2+6$
$6x^2-5x-6=0$
$6x^2+4x-9x-6=0$
$2x(3x+2)-3(3x+2)=0$
$(3x+1)(2x-3)=0$
$x=\frac{3}{2}$
or $x=-\frac{2}{3}$
There are two solutions for the equation, $x=\frac{3}{2}$ or $x=-\frac{2}{3}$
