Answer
$r=\pm4$
Work Step by Step
$2r^2-32=0$
$2r^2=32$
$r^2=16$
$r=\sqrt 16$
$r=\pm 4$
There are two solutions, $ \pm 4$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 564: 29
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