Answer
There are two solutions, $\pm 2$.
Work Step by Step
$3x^2-12=0$
$3x^2=12$
$x^2=4$
$x= \pm 2$
Hence, there are two solutions, $\pm 2$.
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 564: 11
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