Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 564: 31


$z=\pm \sqrt 3$

Work Step by Step

$5z^2-45=0$ $5z^2=45$ $z^2=9$ $z=\sqrt 9$ $z=\pm \sqrt 3$ There are two solutions, $ \pm 3$
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