Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 564: 28

Answer

$p=\pm \sqrt 12$

Work Step by Step

$144-p^2=0$ $p^2=144$ $p^2=\sqrt 144$ $p=\pm \sqrt 12$ There are two solutions, $ \pm 12$.
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