Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 9 - Quadratic Functions and Equations - 9-3 Solving Quadratic Equations - Practice and Problem-Solving Exercises - Page 564: 13


$\pm \sqrt 9$

Work Step by Step

$\frac{1}{3}x^2-3=0$ $\frac{1}{3}x^2=3$ $x^2=9$ $x= \pm \sqrt 9$ Hence, there are two solutions, $x= \pm \sqrt 9$.
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