Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Get Ready! - Page 483: 19

Answer

$81b^6$

Work Step by Step

When we raise a term inside parentheses to a power, we must raise each part of the term to that power, and then multiply. To raise a power to a power, we simply multiply the exponents. Therefore, $$(9b^3)^2=9^2\cdot (b^3)^2=81\cdot b^{3\times 2}=81b^6$$
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