Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Get Ready!: 11

Answer

$24r^2-15r$

Work Step by Step

We start with the given expression: $3(2r+4r^2-7r+4r^2)$ We apply the distributive property by multiplying $3$ by each of the terms inside the parentheses, and adding these products: $$3(2r)+3(4r^2)+3(-7r)+3(4r^2)=6r+12r^2-21r+12r^2$$ We combine like terms (terms with the same exponent) by adding them: $24r^2-15r$
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