Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Get Ready! - Page 483: 23

Answer

$p^{2}q^{3}$

Work Step by Step

Gather like terms $=\displaystyle \frac{p^{4}}{p^{2}}\cdot\frac{q^{9}}{q^{6}}$ Apply rule: $\displaystyle \qquad\frac{a^{m}}{a^{n}}=a^{m-n}$ $=p^{4-2}\cdot q^{9-6}$ =$p^{2}q^{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.