Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Get Ready! - Page 483: 18



Work Step by Step

$=(8\cdot 7)(m^{\frac{3}{5}}\cdot m^{5})$ $=56m^{\frac{3}{5}+5},\qquad$ ...because $a^{m}\cdot a^{n}=a^{m+n}$ $=56m^{\frac{3+25}{5}}$ $=56m^{\frac{28}{5}}$
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