Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Get Ready! - Page 483: 16



Work Step by Step

$=(-3)(-3)\cdot(v^{2}\cdot v^{\frac{1}{2}})$ $=+9\cdot v^{2+\frac{1}{2}},\qquad$ ...because $a^{m}\cdot a^{n}=a^{m+n}$ $=9v^{\frac{4+1}{2}}$ $=9v^{\frac{5}{2}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.