Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Get Ready!: 16

Answer

$9v^{\frac{5}{2}}$

Work Step by Step

$=(-3)(-3)\cdot(v^{2}\cdot v^{\frac{1}{2}})$ $=+9\cdot v^{2+\frac{1}{2}},\qquad$ ...because $a^{m}\cdot a^{n}=a^{m+n}$ $=9v^{\frac{4+1}{2}}$ $=9v^{\frac{5}{2}}$
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