## Algebra 1: Common Core (15th Edition)

$(b^{2}+1)(11b-6)$
$11b^{3}-6b^{2}+11b-6=$ ...factor by grouping- pair up the first with the third term and the second with the last. $=11b(b^{2}+1)-6(b^{2}+1)$ ...use the Distributive Property. $=(b^{2}+1)(11b-6)$