Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 76



Work Step by Step

$11b^{3}-6b^{2}+11b-6=$ ...factor by grouping- pair up the first with the third term and the second with the last. $=11b(b^{2}+1)-6(b^{2}+1)$ ...use the Distributive Property. $=(b^{2}+1)(11b-6)$
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