Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 8 - Polynomials and Factoring - Chapter Review - Page 538: 74


$8m^{2}$ , $3$

Work Step by Step

$8m^{3}+40m^{2}+6m+15=$ ...the first two terms: $8m^{3}=(2\cdot 2\cdot 2\cdot m\cdot m)\cdot m$ $40m^{2}=(2\cdot 2\cdot 2)\cdot 5\cdot(m\cdot m)$ GCF: $8m^{2}$ ...the last two terms. $6m=2\cdot 3\cdot m$ $15=3\cdot 5$ GCF: $3$ Answer: $8m^{2}$ , $3$
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